If 2^x = 3^y = 6^(−z), then 1/x + 1/y + 1/z is equal to

Correct Answer: 0

Subject: History

• 0
• 1
• 3/2
• 1/2

Explanation: Let 2^x = 3^y = 6^(-z) = k. Then 2×3 = 6 ⇒ k^(1/x+1/y) = k^(-1/z) ⇒ 1/x + 1/y + 1/z = 0.

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