150 Questions • 135 Minutes • PYQ Mock Test in Hindi and English
Let B's salary = 100. Then A's salary = 75. Difference = 25. Percentage by which B is more than A = (25/75) × 100 = 33 1/3%.
Let CP = 100x. At 2/3 of fixed value there's a 10% loss, so SP there = 90x. Fixed value = (3/2) × 90x = 135x. Gain% at fixed price = (135x − 100x)/100x × 100 = 35%.
When two articles are sold at the same price, one at R% profit and the other at R% loss, there is always a net loss of R²/100%. Net loss = 15²/100 = 2.25%.
Total(Mon+Tue+Wed) = 3×40 = 120. Total(Tue+Wed+Thu) = 3×41 = 123. Subtracting: Thu − Mon = 3. Since Thu = 42, Mon = 42 − 3 = 39°C.
Let original price = 10 units, reduced price = 9 units. Since expenditure = price × consumption must stay constant, consumption must rise from 9 to 10, i.e. by 1/9 = 11 1/9%.
16y = 32 ⟹ y = 2. Boys = 9×2 = 18. Total = 32+18 = 50. Percentage of girls = (32/50)×100 = 64%.
Pieces = 37.5 × 8 = 300, which is not among the first three options, so the answer is 'None of these'.
Net gain per 2 minutes = 3 m. After 9 minutes it has net-climbed 13.5 m in a repeating up-down pattern; tracking minute-by-minute peaks (6,3,9,6,12,9,15,12,18) shows that in the 11th minute it climbs 6 m from 15 to 21 m, reaching the top before it can slip again. So total time = 11 minutes.
A:B = 2:3, B:C = 1:4 = 3:12. So A:B:C = 2:3:12, sum = 17 parts = 680 ⟹ 1 part = 40. A = 80, B = 120, C = 480.
Let numbers be b (which increases) and a. b + 0.2a = 1.5b ⟹ 0.2a = 0.5b ⟹ a/b = 5/2. So ratio = 5:2.
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