25th February Shift 3RRB JE PYQ

100 Questions • 90 Minutes • PYQ Mock Test in Hindi and English

Sample Questions from this Test

Question 1:

Simar starts from Point A and drives 10 km towards south. He then takes a right turn, drives 7 km, turns right and drives 12 km. He then takes a right turn and drives 9 km. He takes a final right turn, drives 2 km and stops at Point P. How far (shortest distance) and towards which direction should he drive in order to reach Point A again?

(All turns are 90 degree turns only unless specified.)
A.2 km to the west
B.3 km to the west
C.2 km to the east
D.3 km to the east

Direction Analysis: Track Simar's coordinates after each 90° turn. The final point P is 2 km east of A, so A is 2 km west of P.

Final Answer: 2 km to the west.

Question 2:

A tap can fill a cistern in 32 hours, while another tap can empty the full cistern in 64 hours. If the cistern is initially empty and both taps are opened together, find the time (in hours) required to fill one-fourth of the cistern.
A.64
B.48
C.32
D.16

Rate Method: Filling rate = 1/32 and emptying rate = 1/64, so net rate = 1/64 cistern per hour. One-fourth takes 16 hours.

Final Answer: 16.

Question 3:

The list price of a refrigerator is ₹15,000. It is sold to a retailer after two successive discounts of 32% and 40%. The retailer wants to earn a profit of 45% on his cost after allowing a 49% discount (on its new list price) to the customer. At what price should he list the refrigerator?
A.₹17,400
B.₹17,412
C.₹17,325
D.₹17,504

Calculation: Retailer cost = 15000×0.68×0.60 = ₹6,120. Required selling price for 45% profit = ₹8,874. After 49% discount, this is 51% of the new list price, so list price = ₹8,874/0.51 = ₹17,400.

Final Answer: ₹17,400.

Question 4:

D, R, A, W and S have different marks. Only one person has scored between A and R. Only one person has scored between R and W. S has scored more than R and W. How many people have scored less than D?
A.One
B.Two
C.Four
D.Three

Deduction: Apply the stated clues/pattern step by step and eliminate impossible arrangements.

Exam Trick: पहले सबसे restrictive clue/pattern identify करें।

Final Answer: One.

Question 5:

Express 5.9735.97\overline{3} as a vulgar fraction.
A.52192255\frac{219}{225}
B.53192255\frac{319}{225}
C.52292555\frac{229}{255}
D.53192155\frac{319}{215}

Recurring Decimal: Let x=5.97̅3. Subtract the appropriate shifted equations to eliminate the repeating part and reduce to the mixed fraction marked in the source.

Final Answer: 5 219/225.

Question 6:

Select the pair which follows the same pattern as that followed by the two set of pairs given below. Both pairs follow the same pattern.

JKK : KFH
HVO : IQL
A.CPR : DKN
B.OOP : PJM
C.FJL : GDI
D.CUK : DPG

Deduction: Apply the stated clues/pattern step by step and eliminate impossible arrangements.

Exam Trick: पहले सबसे restrictive clue/pattern identify करें।

Final Answer: OOP : PJM.

Question 7:

Why are sulphide ores usually converted into oxides before the extraction of metals?
A.Metal sulphides react faster with carbon
B.Sulphide ores are unstable at room temperature
C.Sulphide ores contain more gangue materials
D.Metal oxides are easier to reduce than sulphides

Key Fact: The question tests the specific concept Metallurgy.

Why the other options are wrong: They do not match the concept tested or the source-marked answer.

Final Answer: Metal oxides are easier to reduce than sulphides.

Question 8:

Under the Stand-Up India Scheme, bank loans from Scheduled Commercial Banks (SCBs) are provided in what range for eligible beneficiaries?
A.₹5 lakh to ₹50 lakh
B.₹25 lakh to ₹2 crore
C.₹1 crore to ₹5 crore
D.₹10 lakh to ₹1 crore

Key Fact: The question tests the specific concept Stand-Up India Scheme.

Why the other options are wrong: They do not match the concept tested or the source-marked answer.

Final Answer: ₹10 lakh to ₹1 crore.

Question 9:

If 4(x2+1)8x3x=6\frac{4(x^2+1)-8x}{3x}=6, x>0x>0, then find the positive value of x+1x\sqrt{x}+\frac{1}{\sqrt{x}}.
A.25\sqrt{\frac25}
B.23\sqrt{\frac23}
C.53\sqrt{\frac53}
D.172\sqrt{\frac{17}{2}}

Algebra: Simplifying the given equation gives the positive value of √x + 1/√x as √(17/2).

Final Answer: √(17/2).

Question 10:

What is the primary composition of the stable composite developed by IIT Mandi that prevents 2D semiconductors from degrading?
A.Carbon nanotubes embedded in polymer matrix
B.Boron nitride mixed with epoxy resin
C.Tungsten disulfide (WS) encapsulated in polydimethylsiloxane (PDMS)
D.Graphene combined with silicone

Key Fact: The question tests the specific concept IIT Mandi Composite.

Why the other options are wrong: They do not match the concept tested or the source-marked answer.

Final Answer: Tungsten disulfide (WS) encapsulated in polydimethylsiloxane (PDMS).

+ 90 more questions inside...