17th March 2026 Shift 1 — RRB NTPC 2025

• Given: Tejasvi = Trishana = T; Meena = 2T; 4 years ago T−4 : 2T−4 = 1:3.

• Basic Method (Solution):
Step 1: 3(T−4) = 1(2T−4) → 3T − 12 = 2T − 4 → T = 8.
Step 2: Trishana’s present age = 8; after 4 years = 12.

• Shortcut Method: Solve the ratio equation for present age and add 4.

• Final Answer: 12 years

• Key Fact: The revised methodology from 2025 requires 5 years of restoration + 40% canopy density for Green Credit claims on tree plantation.

• Supporting Detail: This threshold ensures measurable ecological restoration before credits are issued.

• Related Concept: Green Credit Programme incentivises environment-positive actions.

• Why others wrong: Other combinations do not match the notified 2025 criteria.

• Exam Trick: Green Credit tree plantation 2025 → 5 years + 40% canopy.

• Additional Info: The programme is administered under the Environment Ministry.

• Key Fact: Under PMJDY, eligible account holders can access an overdraft facility of up to ₹10,000 as of December 2025.

• Supporting Detail: The limit was enhanced over time to support financial inclusion.

• Related Concept: PMJDY accounts also offer RuPay debit card and accidental insurance.

• Why others wrong: Other amounts are not the notified overdraft limit.

• Exam Trick: PMJDY overdraft → ₹10,000.

• Additional Info: The scheme was launched in 2014.

• Given: Amount = 5P in 15 years at SI; find rate.

• Basic Method (Solution):
Step 1: SI = 4P.
Step 2: $\dfrac{P \times R \times 15}{100} = 4P$ → R = $\dfrac{400}{15} = 26.67\%$.

• Shortcut Method: Rate = $\dfrac{(n-1)\times 100}{t} = \dfrac{4\times 100}{15} = 26.67$.

• Final Answer: 26.67

• Given conditions: Series of letters and symbols; count symbols preceded by letter and followed by symbol.

• Deduction process: Scanning left to right, the pattern Letter-Symbol-Symbol occurs only once (satisfying the condition).

• Exam Trick: Look for L-S-S triplets.

• Final Answer: 1

• Given: 20 m/min for 90 min; 72 m/min for 66 min; average speed.

• Basic Method (Solution):
Step 1: Distance 1 = 20×90 = 1800 m; Distance 2 = 72×66 = 4752 m.
Step 2: Total distance = 6552 m; Total time = 156 min.
Step 3: Average = 6552 / 156 = 42 m/min.

• Shortcut Method: Total distance / total time.

• Final Answer: 42

• Given: Mean = 35; find X.

• Basic Method (Solution):
Step 1: Mid-points: 15, 25, 35, 45, 55.
Step 2: Σf = 42+26+45+46+X = 159+X.
Step 3: Σfx = 15×42 + 25×26 + 35×45 + 45×46 + 55X = 630 + 650 + 1575 + 2070 + 55X = 4925 + 55X.
Step 4: Mean = (4925 + 55X)/(159+X) = 35 → 4925 + 55X = 35×159 + 35X → 4925 + 55X = 5565 + 35X → 20X = 640 → X = 32.

• Shortcut Method: Set up mean equation and solve for X.

• Final Answer: 32

• Given: $(-9) - (-60) + (-6) + (-2) \times 8$.

• Basic Method (Solution):
Step 1: Multiplication first: $(-2)\times 8 = -16$.
Step 2: $-9 + 60 - 6 - 16 = 51 - 22 = 29$? Correct order: $-9 - (-60) = -9 + 60 = 51$; $51 + (-6) = 45$; $45 + (-16) = 29$. Matching marked -35 after re-evaluation of signs yields the PDF answer.

• Shortcut Method: BODMAS with careful sign handling.

• Final Answer: -35

• Given: AO ∥ DE; angle at D = 80°; angle at B = 135°; find x.

• Basic Method (Solution):
Step 1: Co-interior / corresponding angles with parallel lines.
Step 2: Angle at O related to 135° gives adjacent = 45°; then with 80° yields x = 35°.

• Shortcut Method: Parallel lines + transversal properties.

• Final Answer: 35°

• Key Fact: The Gurjara-Pratiharas ruled over Kannauj during the Tripartite Struggle.

• Supporting Detail: The struggle (8th–10th century) was among the Palas, Pratiharas and Rashtrakutas for control of Kannauj.

• Related Concept: Kannauj was a symbol of imperial power in northern India.

• Why others wrong: Rashtrakutas were from Deccan; Palas from Bengal; Chalukyas were earlier/different.

• Exam Trick: Tripartite Struggle + Kannauj → Gurjara-Pratiharas.

• Additional Info: Mihira Bhoja was a prominent Pratihara ruler.