RRB NTPC Graduate Level (17th March 2026 Shift 3) — RRB NTPC 2025

100 Questions • 90 Minutes • 2025 Mock Test in Hindi and English

Sample Questions from this Test

Question 1:

In 2025, who was named FIFA Men’s Player of the Year at the FIFA Best Football Awards held in Doha, Qatar?
A.Kylian Mbappé
B.Ousmane Dembélé
C.Lionel Messi
D.Erling Haaland

• Key Fact: Ousmane Dembélé was named FIFA Men’s Player of the Year 2025 at the FIFA Best Football Awards in Doha, Qatar.

• Supporting Detail: He was recognised for his outstanding performances in club and international football.

• Related Concept: The FIFA Best Awards honour the world’s best players, coaches and teams.

• Why others wrong: Mbappé, Messi and Haaland were nominees or previous winners but not the 2025 recipient.

• Exam Trick: FIFA Best 2025 Men’s Player → Ousmane Dembélé.

• Additional Info: The awards ceremony is held annually by FIFA.

Question 2:

FKEP is related to EIBL in a certain way based on the English alphabetical order. In the same way, JMHT is related to IKEP. To which of the following is PQNW related, following the same logic?
A.OOLS
B.OQKT
C.OPJS
D.OOKS

• Given conditions: FKEP → EIBL; JMHT → IKEP; find for PQNW.

• Deduction process: Each letter is decreased by 1 in reverse order or specific shift: F→E (−1), K→I (−2), E→B (−3), P→L (−4). Applying same to PQNW yields OOKS.

• Exam Trick: Consistent alphabetical decrement pattern.

• Final Answer: OOKS

Question 3:

The marks scored by 100 students in Mathematics examination are given by the following table. Find the mode of this data (up to 2 decimal places).
Marks scored: 35-44, 45-54, 55-64, 65-74, 75-84, 85-94
No. of students: 10, 20, 30, 25, 10, 5
A.61.17
B.61.67
C.60.56
D.55.44

• Given: Frequency distribution; modal class 55-64 (highest frequency 30).

• Basic Method (Solution):
Step 1: Mode = L + [(f1 − f0)/(2f1 − f0 − f2)] × h.
Step 2: L=55, f1=30, f0=20, f2=25, h=10 → Mode = 55 + [(30−20)/(60−20−25)] × 10 = 55 + (10/15)×10 = 55 + 6.67 ≈ 61.17.

• Shortcut Method: Apply mode formula for continuous series.

• Final Answer: 61.17

Question 4:

Mr. Q travelled 336 km, 925 km and 432 km at a speed of 24 km/hr, 5 km/hr and 12 km/hr, respectively. Find his average speed in km/hr.
A.8 46/235
B.7 51/235
C.7 48/235
D.7 47/235

• Given: Distances 336, 925, 432 km; speeds 24, 5, 12 km/hr; find average speed.

• Basic Method (Solution):
Step 1: Time1 = 336/24 = 14; Time2 = 925/5 = 185; Time3 = 432/12 = 36. Total time = 235 hr.
Step 2: Total distance = 336+925+432 = 1693 km.
Step 3: Average speed = 1693/235 = 7 48/235 km/hr.

• Shortcut Method: Total distance / total time.

• Final Answer: 7 48/235

Question 5:

In which year was the Padhe Bharat Badhe Bharat (PBBB) scheme launched?
A.2014
B.2007
C.2010
D.2018

• Key Fact: The Padhe Bharat Badhe Bharat (PBBB) scheme was launched in 2014.

• Supporting Detail: It is a sub-programme of Sarva Shiksha Abhiyan aimed at improving foundational literacy and numeracy.

• Related Concept: It focuses on early grade reading and mathematics.

• Why others wrong: Other years do not match the launch year of PBBB.

• Exam Trick: PBBB → 2014.

• Additional Info: The scheme emphasises activity-based learning in Classes I and II.

Question 6:

In a certain code language, ‘LIME’ is coded as ‘4839’ and ‘TIME’ is coded as ‘9324’. What is the code for ‘T’ in the given code language?
A.4
B.9
C.3
D.2

• Given conditions: LIME = 4839; TIME = 9324.

• Deduction process: Common letters I,M,E have common codes. Comparing, T corresponds to the unique code 2.

• Exam Trick: Compare common and unique letters.

• Final Answer: 2

Question 7:

According to Article 243Q, the level of municipality for a transitional area will be designated as a _________.
A.Municipal Corporation
B.Township
C.Municipal Council
D.Nagar Panchayat

• Key Fact: According to Article 243Q, a transitional area is designated as a Nagar Panchayat.

• Supporting Detail: Article 243Q classifies municipalities into Nagar Panchayat (transitional), Municipal Council (smaller urban) and Municipal Corporation (larger urban).

• Related Concept: Part IXA of the Constitution deals with Municipalities.

• Why others wrong: Municipal Corporation is for larger urban areas; Municipal Council for smaller urban areas.

• Exam Trick: Transitional area → Nagar Panchayat.

• Additional Info: The 74th Constitutional Amendment introduced these provisions.

Question 8:

What should come in place of ‘?’ in the given series?
7 11 19 31 47 ?
A.67
B.69
C.63
D.65

• Given conditions: 7, 11, 19, 31, 47, ?

• Deduction process: Differences: +4, +8, +12, +16 → next +20. 47 + 20 = 67.

• Exam Trick: Differences increase by 4 each time.

• Final Answer: 67

Question 9:

Which among the following regions saw the Bundela's uprising in 1842?
A.Jabalpur
B.Ganjam
C.Vizianagram
D.Saurashtra

• Key Fact: The Bundela uprising of 1842 took place in the Jabalpur region.

• Supporting Detail: It was a revolt by the Bundela Rajputs against British revenue policies in the Central Provinces.

• Related Concept: It is one of the early 19th-century tribal/peasant uprisings.

• Why others wrong: Ganjam, Vizianagram and Saurashtra saw different revolts.

• Exam Trick: Bundela uprising 1842 → Jabalpur.

• Additional Info: The revolt was suppressed by the British.

Question 10:

Which Articles in the Constitution of India deal with citizenship at the time of its commencement?
A.Articles 14 to 24
B.Articles 1 to 4
C.Articles 12 to 18
D.Articles 5 to 11

• Key Fact: Articles 5 to 11 of the Indian Constitution deal with citizenship at the time of its commencement.

• Supporting Detail: Part II of the Constitution (Articles 5–11) deals with citizenship.

• Related Concept: Article 5 defines citizenship at the commencement; subsequent articles deal with acquisition and termination.

• Why others wrong: Articles 1–4 deal with the Union and its territory; 12–18 and 14–24 deal with Fundamental Rights.

• Exam Trick: Citizenship → Articles 5–11.

• Additional Info: Parliament has power to regulate citizenship under Article 11.

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