RRB NTPC Graduate Level (22nd March 2026 Shift 2) — RRB NTPC 2025

100 Questions • 90 Minutes • 2025 Mock Test in Hindi and English

Sample Questions from this Test

Question 1:

What is the inflation target set by the Government of India under the Monetary Policy Committee framework until April 2026?
A.4% with a tolerance of ±2%
B.3% with a tolerance of ±1%
C.5% with a tolerance of ±2%
D.6% with no specified tolerance

• Key Fact: The Government of India has mandated the Reserve Bank of India (RBI) to maintain retail inflation at 4%4\% with a margin of ±2%\pm 2\%.

• Supporting Detail: This means the comfortable inflation band is between 2%2\% and 6%6\%. This framework is valid until March 31, 2026.

• Related Concept: The Monetary Policy Committee (MPC) uses tools like the repo rate to keep inflation within this targeted band.

• Why others wrong: The other percentages do not reflect the statutory target established by the government in consultation with the RBI under the RBI Act, 1934.

• Exam Trick: Remember the sequence: Target = 4, Lower limit = 2, Upper limit = 6 (i.e., 4±24 \pm 2).

• Additional Info: The MPC consists of 6 members: 3 from the RBI (including the Governor) and 3 external members appointed by the Government.

Question 2:

If 1 is added to each odd digit and 2 is added to each even digit in the number 6134527, what will be the sum of the last and first digits of the new number thus formed?
A.14
B.18
C.12
D.16

• Given conditions: Original number: 6134527. Rule: Odd + 1, Even + 2. Find sum of 1st and last digits in the new number.

• Deduction process:
Step 1: Identify the target digits in the original number to save time.
Original number: 6 1 3 4 5 2 7
First digit = 6 (Even)
Last digit = 7 (Odd)
Step 2: Apply the rules to only these two digits.
New first digit:
6+2=86 + 2 = 8.
New last digit:
7+1=87 + 1 = 8.
Step 3: Find their sum.
Sum
=8+8=16= 8 + 8 = 16.

• Exam Trick: Do not rewrite the entire 7-digit number. Only calculate the new values for the specific positions requested in the final question.

• Final Answer: 16

Question 3:

The period of southwest monsoon season in India is:
A.July to December
B.June to September
C.May to September
D.June to November

• Key Fact: The Southwest Monsoon season in India officially ranges from June to September.

• Supporting Detail: It accounts for approximately 75% of the country's annual rainfall, striking the Kerala coast usually by June 1st and gradually covering the entire country by mid-July.

• Related Concept: The retreating monsoon (Northeast Monsoon) occurs during October and November, bringing rainfall primarily to the southeastern coast (Tamil Nadu).

• Why others wrong: May is considered the pre-monsoon summer season. October-December is the post-monsoon (retreating monsoon) season.

• Exam Trick: SW Monsoon = Summer rains (June-Sept). NE Monsoon = Winter rains (Oct-Dec).

• Additional Info: The monsoon's onset and withdrawal are driven by the shifting of the Inter Tropical Convergence Zone (ITCZ) over the Indian subcontinent.

Question 4:

Based on the English alphabetical order, three of the following four are alike in a certain way and thus form a group. Which is the one that does not belong to that group?
(Note: The odd man out is not based on the number of consonants/vowels or their position in the letter cluster)
A.TYS
B.YCX
C.GKF
D.NRM

• Given conditions: Find the odd letter cluster out of TYS, YCX, GKF, NRM.

• Deduction process:
Check the forward positional jumps between adjacent letters in each cluster.
Option B (YCX): Y(25)
→\rightarrow C(3 or 29). Gap is +4+4. C(29) →\rightarrow X(24). Gap is −5-5. Pattern is +4,−5+4, -5.
Option C (GKF): G(7)
→\rightarrow K(11). Gap is +4+4. K(11) →\rightarrow F(6). Gap is −5-5. Pattern is +4,−5+4, -5.
Option D (NRM): N(14)
→\rightarrow R(18). Gap is +4+4. R(18) →\rightarrow M(13). Gap is −5-5. Pattern is +4,−5+4, -5.
Option A (TYS): T(20)
→\rightarrow Y(25). Gap is +5+5. Y(25) →\rightarrow S(19). Gap is −6-6. Pattern is +5,−6+5, -6.
TYS is the only cluster that does not follow the
+4,−5+4, -5 logic.

• Exam Trick: If a letter jumps past Z (like Y to C), add 26 to the numerical value of the second letter for easy subtraction: C is 3+26=293 + 26 = 29. 29−25=+429 - 25 = +4.

• Final Answer: TYS

Question 5:

In a certain code language, 'ROAD' is coded as '8657' and 'DEAR' is coded as '4567'. What is the code for 'E' in the given code language?
A.5
B.6
C.7
D.4

• Given conditions: ROAD = 8657. DEAR = 4567. Code for E = ?

• Deduction process:
Compare the two words: ROAD and DEAR.
They share three common letters: R, A, D.
Their codes (8657 and 4567) must share three common digits. The common digits are 5, 6, and 7.
The remaining letter in ROAD is 'O', which corresponds to the remaining digit '8'.
The remaining letter in DEAR is 'E', which corresponds to the remaining digit '4'.

• Exam Trick: Cross out the shared digits between the two numbers. The lone digit left in DEAR's code belongs to the lone unique letter 'E'.

• Final Answer: 4

Question 6:

By selling an article at 3/10 of its marked price, Aman incurs a loss of 25%. If he sells it at 69% of its actual marked price, then the profit percentage is
A.75.1%
B.74.1%
C.73.5%
D.72.5%

• Given: Selling Price 1 (SP1SP_1) =310= \frac{3}{10} of Marked Price (MP) =0.3 MP= 0.3 \text{ MP}. Loss at SP1=25%SP_1 = 25\%. New Selling Price (SP2SP_2) =69%= 69\% of MP =0.69 MP= 0.69 \text{ MP}. Find profit percentage.

• Basic Method (Solution):
Step 1: Relate CP, SP, and Loss.
If there is a
25%25\% loss, then SP1SP_1 is 100%−25%=75%100\% - 25\% = 75\% of the Cost Price (CP).
So,
SP1=0.75 CPSP_1 = 0.75 \text{ CP}.
Step 2: Equate the two expressions for
SP1SP_1.
0.3 MP=0.75 CP0.3 \text{ MP} = 0.75 \text{ CP}
Step 3: Express MP in terms of CP.
MP=0.750.3 CP=2.5 CP\text{MP} = \frac{0.75}{0.3} \text{ CP} = 2.5 \text{ CP}.
Step 4: Find the new Selling Price (
SP2SP_2) in terms of CP.
SP2=0.69 MP=0.69×(2.5 CP)=1.725 CPSP_2 = 0.69 \text{ MP} = 0.69 \times (2.5 \text{ CP}) = 1.725 \text{ CP}.
Step 5: Calculate the profit percentage.
Since
SP2=1.725 CPSP_2 = 1.725 \text{ CP}, it means SP2SP_2 is 172.5%172.5\% of CP.
The profit is
172.5%−100%=72.5%172.5\% - 100\% = 72.5\%.

• Shortcut Method: Using ratio comparison directly:
0.3 MPCP=0.75  ⟹  MPCP=0.750.3=2.5\frac{0.3 \text{ MP}}{\text{CP}} = 0.75 \implies \frac{\text{MP}}{\text{CP}} = \frac{0.75}{0.3} = 2.5.
New SP factor
=0.69×2.5=1.725= 0.69 \times 2.5 = 1.725. The decimal part 0.7250.725 translates directly to a 72.5%72.5\% profit.

• Final Answer: 72.5%

Question 7:

In a certain code language, 'REST' is coded as '5729' and 'SEAT' is coded as '7625'. What is the code for 'A' in that language?
A.2
B.5
C.7
D.6

• Given conditions: REST = 5729. SEAT = 7625. Code for A = ?

• Deduction process:
Compare the two words: REST and SEAT.
Common letters: E, S, T.
Codes for REST: 5, 7, 2, 9.
Codes for SEAT: 7, 6, 2, 5.
Common numbers: 5, 7, 2.
Therefore, the common letters (E, S, T) correspond to the common numbers (5, 7, 2) in some order.
The remaining letter in REST is 'R', which must be '9'.
The remaining letter in SEAT is 'A', which must be the remaining number '6'.

• Exam Trick: Cross out the shared digits between the two numbers. The lone digit left in SEAT's code belongs to the lone unique letter 'A'.

• Final Answer: 6

Question 8:

Three friends X, Y and Z started a business by investing a sum of money in the ratio of 9 : 5 : 2. After 6 months, X withdraws half of his capital. If the sum invested by Z is ₹83,000, then out of a total annual profit of ₹88,000, what is the difference between X's and Y's profit?
A.₹11,200
B.₹10,550
C.₹10,945
D.₹12,710

• Given: Initial investment ratio X:Y:Z=9:5:2X:Y:Z = 9:5:2. Z's investment = 83000 (redundant). X withdraws half after 6 months. Total annual profit = 88000. Find difference between X and Y profit.

• Basic Method (Solution):
Step 1: Profit is distributed in the ratio of (Investment
×\times Time).
Step 2: Let the initial investments be
9u,5u,2u9u, 5u, 2u.
Step 3: X's equivalent capital
=(9u×6 months)+(4.5u×6 months)=54u+27u=81u= (9u \times 6 \text{ months}) + (4.5u \times 6 \text{ months}) = 54u + 27u = 81u.
Step 4: Y's equivalent capital
=5u×12 months=60u= 5u \times 12 \text{ months} = 60u.
Step 5: Z's equivalent capital
=2u×12 months=24u= 2u \times 12 \text{ months} = 24u.
Step 6: Profit ratio
X:Y:Z=81u:60u:24u=81:60:24X : Y : Z = 81u : 60u : 24u = 81 : 60 : 24. Divide by 3: 27:20:827 : 20 : 8.
Step 7: Total parts
=27+20+8=55= 27 + 20 + 8 = 55 parts.
Step 8: Value of 1 part
=8800055=1600= \frac{88000}{55} = 1600.
Step 9: Difference between X and Y's profit
=27 parts−20 parts=7 parts= 27 \text{ parts} - 20 \text{ parts} = 7 \text{ parts}.
Step 10: Difference
=7×1600=11200= 7 \times 1600 = 11200.

• Shortcut Method: Ignore the absolute value of Z's investment (83000) as profit sharing only needs the ratio.
Ratio of profits
X:Y:Z=[9×6+4.5×6]:[5×12]:[2×12]=81:60:24=27:20:8X : Y : Z = [9 \times 6 + 4.5 \times 6] : [5 \times 12] : [2 \times 12] = 81 : 60 : 24 = 27 : 20 : 8.
Total
=55= 55 units =88000= 88000.
Diff (X-Y)
=7= 7 units.
Value
=755×88000=7×1600=11200= \frac{7}{55} \times 88000 = 7 \times 1600 = 11200.

• Final Answer: ₹11,200

Question 9:

Which is the latest version of Windows?
A.Windows 18
B.Windows 11
C.Windows 7
D.Windows 10

• Key Fact: Windows 11 is the latest major release of Microsoft's Windows NT operating system, released in October 2021.

• Supporting Detail: It succeeded Windows 10 and introduced a redesigned user interface, a centered Start menu, and native support for Android apps (via the Amazon Appstore).

• Related Concept: Microsoft has moved to a "Windows as a Service" model, continuously updating the core OS rather than releasing completely new numbered versions as frequently as in the past.

• Why others wrong: Windows 10 is the predecessor to 11. Windows 7 is an obsolete older version. Windows 18 does not exist.

• Exam Trick: Don't let imaginary numbers (like 18) confuse you. The progression stopped jumping numbers wildly after 10.

• Additional Info: Windows 11 strictly requires TPM 2.0 (Trusted Platform Module) hardware for security purposes, which made many older PCs incompatible.

Question 10:

The 24th Constitutional Amendment gave the Parliament which of the following powers?
A.Override judicial review
B.Suspend the High Court judgment
C.Suspend elections
D.Amend Fundamental Rights

• Key Fact: The 24th Constitutional Amendment Act of 1971 explicitly restored the absolute power of the Parliament to amend any part of the Constitution, including the Fundamental Rights (Part III).

• Supporting Detail: This amendment was enacted in direct response to the Supreme Court's landmark judgment in the Golaknath case (1967), which had previously ruled that Parliament cannot amend Fundamental Rights.

• Related Concept: It also made it obligatory for the President of India to give his assent to a Constitutional Amendment Bill (he cannot veto or return it).

• Why others wrong: The amendment did not grant powers to suspend elections or High Court judgments. Attempting to completely override judicial review was later struck down as unconstitutional (as judicial review is part of the Basic Structure).

• Exam Trick: The 24th Amendment was all about reversing the Golaknath case restricting Parliament. Therefore, it's about the "power to amend Fundamental Rights".

• Additional Info: The validity of the 24th Amendment was later upheld by the Supreme Court in the famous Kesavananda Bharati case (1973), though with the caveat of the "Basic Structure" doctrine.

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