RRB NTPC Graduate Level (22nd March 2026 Shift 3) — RRB NTPC 2025

100 Questions • 86 Minutes • 2025 Mock Test in Hindi and English

Sample Questions from this Test

Question 1:

Rohit gets double the amount in 6 years when invested at compound interest, compounded annually. In how many years will the amount become sixteen times itself?
A.48
B.12
C.96
D.24

• Given: Amount doubles (22 times) in T1=6T_1 = 6 years. Target: Amount becomes 1616 times in T2=?T_2 = ? years.

• Basic Method (Solution):
Step 1: Formula for compound interest amount is
A=P(1+R100)tA = P(1 + \frac{R}{100})^t.
Step 2:
2P=P(1+R100)6  ⟹  2=(1+R100)62P = P(1 + \frac{R}{100})^6 \implies 2 = (1 + \frac{R}{100})^6.
Step 3: We need the amount to be
16P16P. So, 16=(1+R100)T216 = (1 + \frac{R}{100})^{T_2}.
Step 4: Express
1616 as a power of 22: 16=2416 = 2^4.
Step 5: Substitute
22 from Step 2: 16=[(1+R100)6]4=(1+R100)2416 = [(1 + \frac{R}{100})^6]^4 = (1 + \frac{R}{100})^{24}.
Step 6: Comparing powers,
T2=24T_2 = 24 years.

• Shortcut Method: In compound interest, if a sum becomes xx times in tt years, it becomes xnx^n times in n×tn \times t years. Here, it becomes 22 times in 66 years. We need 1616 times, which is 242^4. So, time required =4×6=24= 4 \times 6 = 24 years.

• Final Answer: 24

Question 2:

Evaluate: 16+20÷4−3×416 + 20 \div 4 - 3 \times 4
A.9
B.8
C.11
D.12

• Given: Mathematical expression 16+20÷4−3×416 + 20 \div 4 - 3 \times 4.

• Basic Method (Solution):
Step 1: Apply the BODMAS rule (Brackets, Orders, Division, Multiplication, Addition, Subtraction).
Step 2: Solve the Division part first.
20÷4=520 \div 4 = 5.
Step 3: The expression becomes:
16+5−3×416 + 5 - 3 \times 4.
Step 4: Solve the Multiplication part next.
3×4=123 \times 4 = 12.
Step 5: The expression becomes:
16+5−1216 + 5 - 12.
Step 6: Solve Addition and Subtraction from left to right.
16+5=2116 + 5 = 21.
21−12=921 - 12 = 9.

• Shortcut Method: Mentally isolate the operations separated by addition/subtraction. Block 1 is 1616. Block 2 is 20÷4=520 \div 4 = 5. Block 3 is 3×4=123 \times 4 = 12. The result is simply 16+5−12=916 + 5 - 12 = 9.

• Final Answer: 9

Question 3:

In accordance with Article 84 of the Constitution of India, which of the following is the minimum age a person must meet to qualify for membership of the House of the People?
A.Twenty-one years
B.Twenty-five years
C.Thirty years
D.Eighteen years

• Key Fact: According to Article 84(b) of the Indian Constitution, the minimum age required to become a member of the House of the People (Lok Sabha) is twenty-five years.

• Supporting Detail: The same article states that the minimum age requirement for the Council of States (Rajya Sabha) is thirty years.

• Related Concept: To be elected as the President or Vice-President of India, or to be appointed as a Governor, the minimum age is 35 years.

• Why others wrong: 18 years is the universal voting age (reduced from 21 by the 61st Amendment). 21 years is the minimum age for contesting Panchayat/Municipality elections. 30 years is for the Rajya Sabha.

• Exam Trick: Lok Sabha (Lower House) = Lower age (25). Rajya Sabha (Upper House) = Upper age (30).

• Additional Info: A candidate must also be a citizen of India and make an oath or affirmation bearing true faith and allegiance to the Constitution.

Question 4:

Which facility, inaugurated in 2025 by the ISRO Chairman, became India's first private-sector navigation innovation hub aimed at strengthening self-reliance in advanced navigation systems?
A.Indian Navigation Research and Innovation Centre
B.National Hub for Advanced Satellite Navigation
C.Ananth Centre of Excellence for Navigation
D.Centre for Indigenous Navigation Technologies

• Key Fact: The 'Ananth Centre of Excellence for Navigation' is India's first private-sector navigation innovation hub, inaugurated in 2025 by the ISRO Chairman.

• Supporting Detail: Established by Ananth Technologies, the center is designed to develop advanced, indigenous navigation technologies supporting India's NavIC (Navigation with Indian Constellation) system and reducing reliance on foreign GPS.

• Related Concept: This aligns directly with the government's push to privatize parts of the space sector and foster deep-tech startups under the IN-SPACe framework.

• Why others wrong: The other options are generic, fabricated names that sound official but do not refer to this specific, groundbreaking private-sector initiative.

• Exam Trick: "Ananth" Technologies is a long-standing, major private partner of ISRO. If a new, major private space hub is opened, it is highly likely associated with them.

• Additional Info: The center focuses on both civilian applications (like smartphones and fleet tracking) and defense requirements.

Question 5:

Which of the following pairs of leaders were closely associated with the signing of the Lucknow Pact of 1916?
A.Dadabhai Naoroji and Surendranath Banerjee
B.Lala Lajpat Rai and Bipin Chandra Pal
C.Gopal Krishna Gokhale and Annie Besant
D.Bal Gangadhar Tilak and Muhammad Ali Jinnah

• Key Fact: The Lucknow Pact of 1916 was a historic agreement reached between the Indian National Congress and the All-India Muslim League, pioneered primarily by Bal Gangadhar Tilak and Muhammad Ali Jinnah.

• Supporting Detail: The pact was highly significant as it marked the reconciliation of the Moderate and Extremist factions of the Congress, while simultaneously forging Hindu-Muslim political unity to demand self-government from the British.

• Related Concept: Through this pact, the Congress controversially agreed to the Muslim League's demand for separate electorates for Muslims in provincial legislatures.

• Why others wrong: Naoroji and Banerjee were early Moderates. Lala Lajpat Rai and Bipin Chandra Pal were part of the extremist Lal-Bal-Pal trio but were not the chief architects of this specific pact. Gokhale passed away in 1915, before the pact was signed.

• Exam Trick: Jinnah was famously hailed as the "Ambassador of Hindu-Muslim Unity" by Sarojini Naidu specifically for his role in architecting the Lucknow Pact alongside Tilak.

• Additional Info: The joint demands included increasing the number of elected members in legislatures and ensuring half of the Viceroy's Executive Council were Indians.

Question 6:

Which of the following is an example of Application Software?
A.MS Excel
B.BIOS
C.Linux
D.Windows

• Key Fact: MS Excel is an example of Application Software, which is designed to help the user perform specific tasks (in this case, creating spreadsheets, crunching numbers, and data analysis).

• Supporting Detail: Application software runs on top of the operating system and is utilized directly by end-users to fulfill particular requirements like word processing, web browsing, or gaming.

• Related Concept: System Software, on the other hand, operates and controls the computer hardware, providing a platform for application software to run.

• Why others wrong: Windows and Linux are Operating Systems (classic examples of System Software). BIOS (Basic Input/Output System) is firmware that initializes hardware during the booting process.

• Exam Trick: If a program is something you actively open to do work or play (Word, Excel, Chrome, Photoshop), it is an Application. If it runs in the background managing the computer itself, it's System Software.

• Additional Info: Software is broadly categorized into System Software, Application Software, and Utility Software (like antiviruses).

Question 7:

While cooking, if the exterior of the cooking vessel becomes blackened, what does it indicate?
A.The food inside is undercooked.
B.The fuel is fully burned.
C.The combustion of the fuel is incomplete.
D.The fuel contains moisture.

• Key Fact: Black soot forming on the bottom of a cooking vessel indicates that the combustion of the fuel is incomplete.

• Supporting Detail: Incomplete combustion occurs when there is a lack of sufficient oxygen to burn the fuel completely. Instead of fully converting to carbon dioxide and water, the fuel leaves behind unburned carbon particles (soot), which deposit on the vessel.

• Related Concept: Complete combustion typically produces a clean, blue flame (like a well-functioning LPG stove), while incomplete combustion produces a yellow/orange, sooty flame.

• Why others wrong: If the fuel were fully burned, there would be no soot (clean blue flame). Undercooked food or moisture in the fuel do not directly cause heavy black soot deposits; the lack of oxygen during burning does.

• Exam Trick: Black soot = Unburned Carbon = Incomplete Combustion.

• Additional Info: In gas stoves, this often happens if the air holes in the burner get blocked, reducing the oxygen supply.

Question 8:

In what duration (in years) will ₹7,200 fetch a simple interest of ₹1,080 at 6% per annum rate of interest?
A.1.5
B.5
C.2.5
D.3.5

• Given: Principal P=₹7200P = ₹7200. Simple Interest SI=₹1080SI = ₹1080. Rate R=6%R = 6\% p.a. Find Time TT.

• Basic Method (Solution):
Step 1: Write down the standard formula for Simple Interest.
SI=P×R×T100SI = \frac{P \times R \times T}{100}
Step 2: Rearrange the formula to solve for Time (
TT).
T=SI×100P×RT = \frac{SI \times 100}{P \times R}
Step 3: Substitute the given values into the formula.
T=1080×1007200×6T = \frac{1080 \times 100}{7200 \times 6}
Step 4: Simplify the expression.
Cancel the two zeros:
T=108072×6T = \frac{1080}{72 \times 6}
72×6=43272 \times 6 = 432
T=1080432T = \frac{1080}{432}
Step 5: Perform the division.
Divide by 108:
1080÷108432÷108=104=2.5\frac{1080 \div 108}{432 \div 108} = \frac{10}{4} = 2.5 years.

• Shortcut Method: Find the interest for 1 year first.
1%1\% of 7200=727200 = 72. So 6%6\% for 1 year is 72×6=43272 \times 6 = 432.
Total interest needed is
10801080.
Time
=1080432=2.5= \frac{1080}{432} = 2.5 years.

• Final Answer: 2.5

Question 9:

The interference of two identical waves moving in opposite directions produces:
A.Incident Waves
B.Standing Waves
C.Longitudinal Waves
D.Transversal waves

• Key Fact: When two identical waves (having the same frequency and amplitude) travel in opposite directions and interfere with each other, they produce a 'Standing Wave' (or stationary wave).

• Supporting Detail: In a standing wave, the wave profile does not appear to move forward through the medium. Instead, it oscillates vertically in place, creating points of zero amplitude (nodes) and points of maximum amplitude (antinodes).

• Related Concept: This phenomenon is commonly observed in musical instruments, such as a plucked guitar string (where the wave reflects back from the fixed ends) or air columns in flutes.

• Why others wrong: Incident waves are just waves striking a boundary. Longitudinal and Transverse refer to the direction of particle vibration relative to wave propagation, not the result of opposite interference.

• Exam Trick: "Moving in opposite directions" + "Interference" = Standing Wave (because they effectively cancel each other's forward momentum, standing still).

• Additional Info: The distance between two consecutive nodes or antinodes in a standing wave is exactly half the wavelength (λ/2\lambda/2).

Question 10:

In a race of 1200 metres, Amit gives Bhushan a head-start of 200 metres. Amit starts 20 seconds after Bhushan. Amit overtakes Bhushan 4 minutes after he (Amit) starts running. Amit finishes the race 10 seconds before Bhushan. What is the running speed (in m/s) of Amit?
A.3493 \frac{4}{9}
B.4134 \frac{1}{3}
C.4494 \frac{4}{9}
D.3133 \frac{1}{3}

• Given: Race = 1200m. Amit runs 1200m, Bhushan runs 1200−200=10001200-200 = 1000m. Amit starts 20s later. Amit overtakes 4 mins (240s) after Amit starts. Amit finishes 10s before Bhushan. Find Amit's speed (VAV_A).

• Basic Method (Solution):
Step 1: Let Amit's speed be
VAV_A and Bhushan's speed be VBV_B.
Step 2: Analyze the overtake condition.
Amit runs for 4 minutes
=240= 240 seconds. Distance Amit runs =240VA= 240 V_A.
Bhushan started 20 seconds earlier. So Bhushan has been running for
240+20=260240 + 20 = 260 seconds. Distance Bhushan runs =260VB= 260 V_B.
Since Amit overtakes Bhushan, their absolute position from the start line is identical. Bhushan had a 200m head start.
Equation 1:
240VA=200+260VB240 V_A = 200 + 260 V_B.
Step 3: Analyze the finish condition.
Amit's total time to run 1200m
=1200VA= \frac{1200}{V_A}.
Bhushan's total time to run 1000m
=1000VB= \frac{1000}{V_B}.
Amit started 20s late and finished 10s early. This means Amit's running time is exactly 30 seconds less than Bhushan's running time.
Equation 2:
1200VA=1000VB−30  ⟹  1000VB=1200VA+30\frac{1200}{V_A} = \frac{1000}{V_B} - 30 \implies \frac{1000}{V_B} = \frac{1200}{V_A} + 30.
Step 4: Solve the equations.
From Eq 1:
24VA=20+26VB  ⟹  12VA=10+13VB  ⟹  13VB=12VA−10  ⟹  VB=12VA−101324V_A = 20 + 26V_B \implies 12V_A = 10 + 13V_B \implies 13V_B = 12V_A - 10 \implies V_B = \frac{12V_A - 10}{13}.
Substitute
VBV_B into Eq 2:
100012VA−1013=1200VA+30\frac{1000}{\frac{12V_A - 10}{13}} = \frac{1200}{V_A} + 30
1300012VA−10=1200+30VAVA\frac{13000}{12V_A - 10} = \frac{1200 + 30V_A}{V_A}
130012VA−10=120+3VAVA\frac{1300}{12V_A - 10} = \frac{120 + 3V_A}{V_A}
1300VA=(12VA−10)(120+3VA)1300V_A = (12V_A - 10)(120 + 3V_A)
1300VA=1440VA+36VA2−1200−30VA1300V_A = 1440V_A + 36V_A^2 - 1200 - 30V_A
1300VA=36VA2+1410VA−12001300V_A = 36V_A^2 + 1410V_A - 1200
36VA2+110VA−1200=036V_A^2 + 110V_A - 1200 = 0
Divide by 2:
18VA2+55VA−600=018V_A^2 + 55V_A - 600 = 0
Using quadratic formula:
VA=−55±3025−4(18)(−600)36=−55±3025+4320036=−55±4622536=−55±21536V_A = \frac{-55 \pm \sqrt{3025 - 4(18)(-600)}}{36} = \frac{-55 \pm \sqrt{3025 + 43200}}{36} = \frac{-55 \pm \sqrt{46225}}{36} = \frac{-55 \pm 215}{36}.
Since speed is positive:
VA=16036=409=449V_A = \frac{160}{36} = \frac{40}{9} = 4\frac{4}{9} m/s.

• Shortcut Method: Use the options to satisfy the equations.
Option C gives
VA=40/9V_A = 40/9.
From
12VA=10+13VB12V_A = 10 + 13V_B, 12(40/9)=160/312(40/9) = 160/3.
13VB=160/3−30/3=130/3  ⟹  VB=10/313V_B = 160/3 - 30/3 = 130/3 \implies V_B = 10/3.
Check the time gap:
Amit's time
=1200/(40/9)=30×9=270= 1200 / (40/9) = 30 \times 9 = 270s.
Bhushan's time
=1000/(10/3)=300= 1000 / (10/3) = 300s.
The difference is 30s. Since Amit starts 20s late and finishes 10s early, his running duration should be exactly 30s less. It matches perfectly!

• Final Answer: 4494 \frac{4}{9}

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