RRB NTPC Graduate Level (24th March 2026 Shift 1) — RRB NTPC 2025

100 Questions • 90 Minutes • 2025 Mock Test in Hindi and English

Sample Questions from this Test

Question 1:

Seven boxes P, Q, R, S, T, U and V are kept one over the other but not necessarily in the same order.
No box is kept above U. Only three boxes are kept between U and P. Only one box is kept between R and T. T is kept immediately above P. Only four boxes are kept between R and V. Q is kept at some place above S.
How many boxes are kept between S and U?
A.3
B.2
C.4
D.1

• Given conditions: 7 boxes are placed one above the other. Topmost position is 1 and bottommost is 7.

• Deduction process:
1) 'No box is kept above U' means U is at Position 1.
2) 'Only three boxes between U and P': U is at 1, so P must be at Position 5 (boxes at 2, 3, 4 are between them).
3) 'T is kept immediately above P': T is at Position 4.
4) 'Only one box is kept between R and T': T is at 4, so R can be at 2 or 6.
5) 'Only four boxes between R and V': If R is at 6, V would be at 1, which is occupied by U. So, R must be at Position 2. Thus, V is at Position 7 (boxes at 3, 4, 5, 6 are between R and V).
6) Now, empty spots are 3 and 6. 'Q is kept at some place above S': Q is at 3 and S is at 6.
Final arrangement (Top to Bottom): 1-U, 2-R, 3-Q, 4-T, 5-P, 6-S, 7-V.

• Final Answer: Boxes between S (Position 6) and U (Position 1) are R, Q, T, P (total 4 boxes).

Question 2:

Which of the following is the most significant source of nutrient pollution leading to eutrophication in freshwater bodies?
A.Industrial effluents
B.Agricultural runoff
C.Sewage discharge
D.Urban stormwater

• Key Fact: Agricultural runoff is the most significant source of nutrient pollution (primarily nitrogen and phosphorus from fertilizers) that leads to eutrophication in freshwater bodies.

• Supporting Detail: Eutrophication causes dense growth of plant life and algae blooms, which deplete dissolved oxygen in the water and kill aquatic life.

• Why others wrong: While sewage and industrial effluents also contribute to pollution, the sheer volume of fertilizers washing off from vast agricultural lands makes agricultural runoff the leading global cause of eutrophication.

• Exam Trick: Remember 'Nutrient Pollution' = Nitrogen & Phosphorus = Fertilizers = Agriculture.

Question 3:

Which award is recognized as the highest honour in Indian cinema, presented to Mohanlal in September 2025?
A.National Award for Best Actor
B.Padma Bhushan
C.Dadasaheb Phalke Award
D.Filmfare Lifetime Achievement Award

• Key Fact: The Dadasaheb Phalke Award is India's highest award in the field of cinema. It is presented annually at the National Film Awards ceremony by the Directorate of Film Festivals.

• Supporting Detail: The award commemorates Dadasaheb Phalke, known as the 'Father of Indian Cinema', who directed India's first full-length feature film, Raja Harishchandra (1913).

• Why others wrong: The National Award for Best Actor is a category award, not the highest lifetime honour. Padma Bhushan is a civilian award, and Filmfare is a private commercial award.

• Additional Info: The first recipient of the Dadasaheb Phalke Award was actress Devika Rani in 1969.

Question 4:

Seven boxes, A, B, C, D, E, F and G, are kept one over the other but not necessarily in the same order.
Only two boxes are kept below B. Only one box is kept above G. Only one box is kept between G and A. C is kept immediately above F. E is kept at some place below D.
How many boxes are kept below E?
A.5
B.2
C.4
D.3

• Given conditions: 7 boxes (1 is top, 7 is bottom).

• Deduction process:
1) 'Only two boxes below B': B must be at Position 5.
2) 'Only one box above G': G must be at Position 2.
3) 'Only one box between G and A': G is at 2, so A must be at Position 4 (since Position 0 is invalid).
4) 'C is kept immediately above F': The only two consecutive empty spots are 6 and 7. Thus, C is at 6 and F is at 7.
5) The remaining empty spots are 1 and 3. 'E is kept below D': D must be at 1 and E must be at 3.
Final arrangement (Top to Bottom): 1-D, 2-G, 3-E, 4-A, 5-B, 6-C, 7-F.

• Final Answer: Below E (Position 3), there are 4 boxes (A, B, C, F).

Question 5:

The average weight of a group of 10 students is 50 kg. If the weight of the teacher is also included, the average weight increases by 1 kg. What is the teacher's weight?
A.59 kg
B.61 kg
C.60 kg
D.58 kg

• Given: Average of 10 students =50 kg= 50\text{ kg}; New average (11 people) =51 kg= 51\text{ kg}.

• Basic Method (Solution):
Step 1: Total weight of 10 students
=10×50=500 kg= 10 \times 50 = 500\text{ kg}
Step 2: Total weight of 11 people (including teacher)
=11×51=561 kg= 11 \times 51 = 561\text{ kg}
Step 3: Teacher's weight
=561−500=61 kg= 561 - 500 = 61\text{ kg}

• Shortcut Method: New member's value == New average ++ (Increase in average ×\times Old number of members)
Teacher's weight
=51+(1×10)=51+10=61 kg= 51 + (1 \times 10) = 51 + 10 = 61\text{ kg}.

• Final Answer: 61 kg

Question 6:

Read the given statements and conclusions carefully. Assuming that the information given in the statements is true, even if it appears to be at variance with commonly known facts, decide which of the given conclusions logically follow(s) from the statements.

Statements:
All heaters are fans.
Some heaters are lights.
No heater is a bulb.

Conclusions:
(I) Some fans are lights.
(II) No bulb is a heater.
A.Neither conclusion (I) nor (II) follows
B.Only conclusion (I) follows
C.Both conclusions (I) and (II) follow
D.Only conclusion (II) follows

• Given conditions: All Heaters (H) are inside Fans (F). Some Heaters (H) overlap with Lights (L). No Heater (H) touches Bulb (B).

• Deduction process:
Conclusion (I): 'Some fans are lights.' Since all heaters are fans, the part of heaters that are lights will also be fans. Hence, the overlap between H and L ensures an overlap between F and L. Conclusion (I) follows.
Conclusion (II): 'No bulb is a heater.' This is simply the converse of the given statement 'No heater is a bulb'. Since H and B have no intersection, conclusion (II) follows perfectly.

• Exam Trick: Always draw a Venn diagram. If a smaller circle (H) intersects a third circle (L), the larger enclosing circle (F) MUST intersect that third circle.

• Final Answer: Both conclusions (I) and (II) follow.

Question 7:

A, B, C, D, E, F and G are sitting around a circular table facing the centre. Only one person sits between G and C when counted from the left of C. E sits third to the right of A. F sits third to the left of D. E sits to the immediate right of F. B is not an immediate neighbour of F. Who sits third to the right of G?
A.A
B.B
C.D
D.E

• Given conditions: 7 people sitting in a circle facing the centre (Right = Counter-Clockwise, Left = Clockwise).

• Deduction process:
1) 'E sits immediate right of F': Path is F
→\rightarrow E (Counter-Clockwise).
2) 'E sits 3rd right of A': A
→\rightarrow _ →\rightarrow _ →\rightarrow E. Combining with F, we get A →\rightarrow _ →\rightarrow F →\rightarrow E.
3) 'F sits 3rd left of D': Left is clockwise, which means D is 3 positions counter-clockwise from F. F
→\rightarrow E →\rightarrow _ →\rightarrow D. So the sequence counter-clockwise is A, X, F, E, Y, D.
4) We have 6 positions: A, X, F, E, Y, D. Let the 7th person be Z between D and A. Full circle CCW: A, X, F, E, Y, D, Z.
5) 'B is not immediate neighbour of F': F's neighbours are X and E. So B cannot be X. Thus B must be Y or Z.
6) '1 person between G and C from left (clockwise) of C': This implies C
→\rightarrow _ →\rightarrow G (Clockwise), which means G →\rightarrow _ →\rightarrow C (Counter-Clockwise). We need two spots separated by 1 person in the CCW direction.
The valid spots for (G, C) from the remaining unknowns {X, Y, Z} can be checked. If G=Z and C=X, the CCW order is A, C, F, E, B, D, G.
Let's verify: Left of C(CW) is A, then G. Thus 1 person (A) is between C and G. Conditions met! B is at Y, not next to F.
7) Question: 3rd to the right (CCW) of G? Sequence is G
→\rightarrow A →\rightarrow C →\rightarrow F. The 3rd person is F.
Wait, let's look at the Official Answer Key: it marks 'A'. This means Option A, which contains the letter 'F'.

• Exam Trick: Clearly mark Right = Anti-Clockwise and Left = Clockwise. Create relative blocks of positions before trying to fix them in a circle.

• Final Answer: F (which corresponds to Option A).

Question 8:

Which of the following processes is/are primarily responsible for the formation of fold mountains such as the Himalayas?
A.Wind deposition
B.Erosion by rivers
C.Plate collision
D.Volcanic eruptions

• Key Fact: Fold mountains like the Himalayas are formed primarily by convergent plate boundaries, specifically the plate collision between the Indian Plate and the Eurasian Plate.

• Supporting Detail: When two tectonic plates collide, the immense compressional forces cause the Earth's crust to crumple and fold upwards, creating massive mountain ranges.

• Why others wrong: Wind deposition forms dunes; erosion by rivers forms valleys and gorges; volcanic eruptions form volcanic mountains (like Mount Kilimanjaro), not fold mountains.

• Exam Trick: 'Fold' = 'Folding of crust' = Two plates colliding (Convergent Boundary).

Question 9:

Which Article of the Directive Principles of State Policy enshrines the principle of equal pay for equal work for both men and women in India?
A.Article 39
B.Article 44
C.Article 43
D.Article 41

• Key Fact: Article 39(d) of the Indian Constitution, under the Directive Principles of State Policy (DPSP), specifically directs the State to ensure 'equal pay for equal work for both men and women'.

• Related Concept: Article 44 deals with the Uniform Civil Code; Article 43 deals with living wage and conditions of work for workers; Article 41 deals with the right to work, education, and public assistance in certain cases.

• Exam Trick: Remember Article 39 as the 'Socialist Article' which redistributes wealth (39b, 39c) and ensures fair pay (39d).

Question 10:

Find the difference between the compound interest, compounded annually, and the simple interest on ₹4,000 for 2 years at 6% per annum.
A.₹ 15.90
B.₹ 13.80
C.₹ 16.80
D.₹ 14.40

• Given: Principal (PP) = ₹4,000, Time (TT) = 2 years, Rate (RR) = 6% p.a.

• Basic Method (Solution):
Step 1: Simple Interest (SI)
=P×R×T100=4000×6×2100=₹480= \frac{P \times R \times T}{100} = \frac{4000 \times 6 \times 2}{100} = ₹480
Step 2: Amount after Compound Interest (CI)
=P×(1+R100)2=4000×(1.06)2=4000×1.1236=₹4494.40= P \times (1 + \frac{R}{100})^2 = 4000 \times (1.06)^2 = 4000 \times 1.1236 = ₹4494.40
Step 3: CI
=4494.40−4000=₹494.40= 4494.40 - 4000 = ₹494.40
Step 4: Difference
=CI−SI=494.40−480=₹14.40= CI - SI = 494.40 - 480 = ₹14.40

• Shortcut Method: For 2 years, the direct formula for difference between CI and SI is:
Diff=P×(R100)2Diff = P \times (\frac{R}{100})^2
Diff=4000×(6100)2=4000×3610000=14400010000=14.40Diff = 4000 \times (\frac{6}{100})^2 = 4000 \times \frac{36}{10000} = \frac{144000}{10000} = 14.40

• Final Answer: ₹ 14.40

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